Jimmy Bravo has an automobile repair service, which caters to four-wheelers and two wheelers.In the first week of April,Jimmy repaired 120 tyers and 58 engines.How many two-wheelers did he serve that week? The options are 56,38,64 and 44.
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Let us assume that, Jimmy Bravo repaired x two-wheelers and y four-wheelers .
so,
→ x + y = 58 ----------- Eqn.(1)
→ 2x + 4y = 120 ----------- Eqn.(2)
Multiply Eqn.(1) by 4 and subtracting Eqn.(2) from result,
→ 4(x + y) - (2x + 4y) = 58 * 4 - 120
→ 4x - 2x + 4y - 4y = 232 - 120
→ 2x = 112
→ x = 56 (Ans.)
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