Math, asked by Anonymous, 10 months ago

Jisha is 5 years younger than Thavan. Four years later, Thavan will be twice as old as Jisha. Find their present ages.

Answers

Answered by shivanisingh772277
10

Answer:

age of bhavan and nisha is

6 year and 1 year respectively

let the present age of Tha van be x

then jisha age=x-5

after four year-

thavan age =x+4

and jisha age=x-5+4=x-1

now,

according to question,

x+4=2(x-1)

x+4=2x-2

4+2=2x-x

6=x

so the present age of thavan is 6 years and age of nisha is 1 year

Answered by Anonymous
27

 \large\bf\underline{Given:-}

  • Jisha is 5 years younger then Thavan
  • Four years later Thavan will be twice as old as jisha

 \large\bf\underline {To \: find:-}

  • Present age of Jisha and Thavan

 \huge\bf\underline{Solution:-}

◑ Let the age of Jisha be x years.

◑ Let the age of Thavan be y years.

It is given in the Question that Jisha is 5 years younger than Thavan.

then, Thavan age = x - 5 [Given]

According to Question:-

Four years later, Thavan will be twice as old as Jisha.

Four years later thier ages :-

  • ≫ Age of Jisha = x + 4
  • ≫ Age of Thavan = y + 4

↣x + 4 = 2(x - 5 + 4)

↣x + 4 = 2(x - 1)

↣ x + 4 = 2x - 2

↣ 4 + 2 = 2x - x

↣x = 6

hence,

  • »★Age of Jisha x = 6 years
  • »★ Age of Thavan (x -5)= 1 year

\rule{200}3

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