Question

jisme dam ho krke dikhao

..............tag here u as a mathematician....................​

Answer 1

Answer:

S1=3-4= -1

S2= 3(2)^2 - 4×2=12-8=4

Now we know S1=a1

a2=S2-S1

a2=4-(-1)=5

Now d = a2-a1= 5-(-1)=6

an= (-1)+(n-1)6= -1+6n-6 = 6n-7

Answer 2

Answer:

6n - 7

Step-by-step explanation:

Given:

Sₙ = 3n² - 4n

Then,

Sₙ₋₁ = 3(n - 1)² - 4(n - 1)

Now,

Sₙ - Sₙ₋₁ = (3n² - 4n) - {3(n - 1)² - 4(n - 1)}

nth term:

aₙ = (3n² - 4n) - {3(n² - 2n + 1) - 4n + 4}

  = 3n² - 4n - {3n² - 6n + 3 - 4n + 4}

  = 3n² - 4n - 3n² + 10n - 7

  = 6n - 7

Therefore,

Required nth term = 6n - 7.

dam ho brainliest krke dikhao.