Question

Jiya’s mother is 12 years more than twice her age. After 8 years, her mother’s age
will be 20 years less than three times her age. Find Jiya’s age and her mother’s age.

Answer 1

Answer:

Let Jiya's age be x years

Mother's age=2x+12 years

According to question:-

2x+12+8=3x-20

2x+20=3x-20

3x-2x=20+20

x=40

Jiya's present age= 40 years

Mother's present age=2x+12

= 40(2)+12

=80+12

=92 years

Answer 2

Given: Jiya's mother is 12 years more than twice her age. After 8 years her mother's age will be 20 years less than three times her age.

To find: Jiya's and her mother's age

Explanation: Let Jiya's age be x.

Her mother's age is 12 more than twice her age.

Then, her mother's age= 2x +12

After 8 years, Jiya's age= x+8

Her mother's age= 2x+12+8= 2x+20

Her mother's age is 20 years less than thrice her age.

Then,

2x+20 = 3(x+8)-20

=> 2x+20 = 3x+24-20

=> 2x+20 = 3x+4

=> 20-4 = 3x-2x

=> x= 16

Jiya's age= 16 years

Mother's age= 2x+12

=2*16+12

= 44 years

Therefore, Jiya's age is 16 years and her mother's age is 44 years.