Question

Jiya walks 6km due east and then 8km due north. How far is she from her starting point?

Answer 1

this can be solved as a triangle.as she walks 6 km east then 8km north the angle formed there is 90 degrees.pythagoras theorem can be used.then the ans will be
6x6+8x8=100
then distance covered by her is 100 km

Answer 2

Let the starting point be a AB is 6km and BC is 8Km
/_ABC =90
Then by PGT
AC^2=BC^2+AB^2
AC=√6^2+8^2
AC=√36+64
AC=√100
AC=10KM