Question

JjFind the smallest number divisible by both 306 and 657.

Answer 1

ANSWER:

The smallest number divisible by both 306 and 657 is 22338.

EXPLANATION:

To calculate the smallest number divisible by both A and B, we need to take LCM (least common multiple) of A and B.

Hence, the smallest number divisible by both 306 and 657 = LCM of 306 and 657 = 22338

Answer 2

The smallest number divisible by both 306 and 657 is 22338.

This can be determined by using the method of prime factorization.

The prime factorization of the given numbers:

306 = 2 × 3 × 3 × 17 = 2 × 3^2 × 17

657 = 3 × 3 × 73 = 3^2 × 73

We take the prime factors with the largest exponents.

Least common multiple( LCM) of the two numbers : 2× 3^2 × 17 × 73 = 22338.

Therefore, the smallest number divisible by both the numbers is 22338.