JKLM is a square.Points P and Q are outside the square such that triangles JPM and MLQ are both equilateral. The size in degrees of angle PQM is
a)10
b)15
c)25
d)30
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Answer:b
Step-by-step explanation:
as ∠ JPM = ∠ PMJ = ∠PJM = 60°
also ∠QML =∠ MQL = ∠ MLQ = 60°
also PM = MQ (JM =ML and ΔPJM and ΔMQL are equilateral )
∴ In ΔPMQ,
∠PMQ = ∠MQP (angles opposite to equal sides of a Δ are equal)
Also, ∠JML + reflex∠JML= 360°
⇒reflex∠JML=270°(360-90)
Also, reflex∠JML= ∠JPM+∠PMQ+∠QML
270°=60°+∠PMQ+60°
270-120=∠PMQ
∠PMQ=150°
∴ In ΔPMQ,
∠PMQ+∠QPM+∠MQP=180°(Angle sum property of Δ)
∠PMQ+150°+∠MQP=180°
2∠PQM=180°-150°
2∠PQM=30°
∴∠PQM=30/2
∠PQM=15°
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