Question

jldi 39 no. solve karo​

Answer 1

Answer:

$2 {x}^{2} - 5x - 3 = 0 \\ \\ 2 {x}^{2} - 6x + x - 3 = 0 \\ \\ 2x(x - 3) + 1(x - 3) = 0 \\ \\ x = - \frac{1}{2} \: \: \: \: \: \: \: \: \: x = 3 \\ \\ roots \: \: of \: \: equation \: \: {x}^{2} + px + q = 0 \: \: is \: \: - \frac{1}{4} \: \: and \frac{3}{2} \\ \\ - p = \frac{3}{2} - \frac{1}{4} = \frac{5}{4} \\ \\ p = - \frac{5}{4} \\ \\ q = - \frac{3}{8}$

Answer 2

i hope this is helpfull for u ..