Question

jldi ans do sharif bcha padh rha hai

photo clear nhi hai yeh bahana mt marna xd..xd..​

Answer 1

$= \frac{ \tan(x) }{ \sec(x) - 1 } + \frac{ \tan(x) }{ \sec(x) + 1 } \\ = \frac{ \frac{ \sin(x) }{ \cos(x) } }{ \frac{1}{ \cos(x) } - 1 } + \frac{ \frac{ \sin(x) }{ \cos(x) } }{ \frac{1}{ \cos(x) } + 1 } \\ = \frac{ \sin(x) }{ \cos(x) } \times \frac{ \cos(x) }{1 - \cos(x) } + \frac{ \sin(x) }{ \cos(x) } \times \frac{ \cos(x) }{1 + \cos(x) } \\ = \frac{ \sin(x) }{1 - \cos(x) } + \frac{ \sin(x) }{1 + \cos(x) } \\ = \sin(x) (\frac{1}{1 - \cos(x) } + \frac{1}{1 + \cos(x) } ) \\ = \sin(x) ( \frac{1 + \cos(x) + 1 - \cos(x) }{1 - { \cos }^{2}x } ) \\ = \frac{2 \sin(x) }{ \sin^{2} } \\ = \frac{2}{ \sin(x) } \\ = 2 \csc(x)$