Question

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Answer 1

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★ The length and the breadth are in ratio 4 : 3 and its height is 5.5 m . The cost of decorating its walls at 6.60 Rs per m² is 5082 Rs . Find lengthand breadth ..

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• Let the ratios be 4x and 3x

It means ,

• Length = 4x
• Breadth = 3x

→ Finding Total Surface Area ( T.S.A. )

$\mapsto \rm\: csa \: = 2 h\: (l + b)$

$\mapsto \rm \: csa \: = 2 \times 5.5 \times (4x + 3x)$

$\mapsto \rm \: csa \: = 11 \times (7x)$

$\mapsto \rm \: csa \: = 77x$

→ Cost of decorating

$\star \rm \: cost \: of \: decoration \: = csa \: \times \: rate$

$\mapsto \rm\: 5082 = (77x) \times 6.6$

$\mapsto \rm \: 770 = 77x$

$\mapsto \rm \: x = 10$

Now , Putting the value of x to Find L & B

• L = 4x = 40m
• B = 3x = 30m

{Vaise , blanks me kya tha ...xD}