Math, asked by ayushthakur72, 1 year ago

Jldi se bta do frnds ​

Attachments:

Answers

Answered by mysticd
0

Answer:

Option (A)

Explanation:

Compare px²+qx+m =0 with

ax²+bx+c=0 , we get

a = p , b = q , c = m

i ) sum of the roots = -b/a

=> sinA+cosA = -q/p ----(1)

ii) product of the roots = c/a

=> sinAcosA = m/p-----(2)

On Squaring equation (1) , we

get

=> (sinA+cosA)² = (-q/p)²

=> sin²A+cos²A+2sinAcosA=q²/p²

=> 1+2(m/p) = q²/p²

=> (p+2m)/p = q²/p²

=> p(p+2m) = q²

=> p²+2pm = q²

=> p²+2pm+m²=q²+m²

=> (p+m)² = q²+m²

Therefore,

Option (A) is correct.

••••


ayushthakur72: thnku
Similar questions