Jldi se bta do frnds
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Answer:
Option (A)
Explanation:
Compare px²+qx+m =0 with
ax²+bx+c=0 , we get
a = p , b = q , c = m
i ) sum of the roots = -b/a
=> sinA+cosA = -q/p ----(1)
ii) product of the roots = c/a
=> sinAcosA = m/p-----(2)
On Squaring equation (1) , we
get
=> (sinA+cosA)² = (-q/p)²
=> sin²A+cos²A+2sinAcosA=q²/p²
=> 1+2(m/p) = q²/p²
=> (p+2m)/p = q²/p²
=> p(p+2m) = q²
=> p²+2pm = q²
=> p²+2pm+m²=q²+m²
=> (p+m)² = q²+m²
Therefore,
Option (A) is correct.
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ayushthakur72:
thnku
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