Question

jo 2 jagah red mark Kiya h vo kaise aaya bas ye Bata do. ​

Answer 1

Answer:

its simple..as you see in question v-t graph is given the max value for v is 20 (given ) and time is also= 20 in three intervals

first interval 0 to 5, second 5 to 15 and third is 15 to 20

here for calculate distance we have to calculate area of this whole graph so,

area of graph ABCD = area of triangle AEB (which is equal to 1/2×base ×height means 1/2 × AE×BE=1/2×5×20=50) + area of rectangle BCFE(which is equal to length×breath =10×200=200) + area of triangle DFC(which is equal to 1/2×b×h = 1/2×5×20 = 50)

area of graph ABCD = 50+200+50 = 300m

● vo red box me aapka rectangle EFDC ka area hai l×b = 10 ×20 =200 {vha pr 11 ki jgah 10 hoga.. correct it }

●niche red box me aapne galat answer likha hai vha pr BC =200 m hoga.. correct it

●distance between AB=50m

BC =200m

CD = 50m

total = 300m

Hope this will help you :)

Answer 2

Answer:

total = 300 . m

hope it help you