Question

Jo . A BE с In the above AABC, AB || DE , ZABC = QPD. E ZDCP = 20° and QC is the bisector of ZACB, the find ZBAC (1) 20° (2) 40° (3) 60° (4) 80° 51.​

Answer 1

Answer:

Applying basic proportionality theorem, we get

AD

DC

=

BE

EC

2x

x+3

=

2x−1

x

(x+3)(2x−1)=x(2x)

2x

2

−x+6x−3=2x

2

5x=3

x=

5

3