Question

Jo bhi is question ko answer kare ga yani vo NEET phod ke ayega ? ​

Answer 1

Answer:

(d) Unit of T is same as that of P

Explanation:

Heya friend !

Let's see the question :-

$y = acos(\frac{t}{p}-qx )$

Now,

We know that the terms which are followed by the function cos are to be treated as angle. So,

We can see their dimension / unit will be same, i.e.

[$\frac{t}{p} -qx$] = [Ф]

$\frac{t}{p} - qx = [M^{0}L^{0} T^{0}  ]$

Now,

Let's assume something

[NOTE - THIS IS ONLY FOR UNDERSTANDING THE CONCEPT]

Let a = 5 m and b = 25 sec,

so what will be = b - a ? Nothing ! because we can only subtract quantities having same unit / dimension (for e.g. :-- [10m - 5m] or [25sec-10sec])

So,

we can see,

[$\frac{t}{p}$] = [qx] = [Ф]

Now,

we are dividing t by p, then

[t] = [p]

and, similarly ,

[q] = [$\frac{1}{x}$]

So,

The correct option is:-

(d) Unit of T is same as that of P

Thanks !

#BAL #answerwithquality

Answer 2

Answer is (d)

Explanation:

• It is known that angles are expressed in radians which is a dimensionless quantity
• So everything in the cosine should be dimensionless
• For that to happen, the dimensions of p should cancel t
• So p and t should have same dimension :)

Don’t hesitate to consult for doubt in the comments below and Don't forget to mark it the brainliest if it helps.. #BAL #answerwithquality