Question

jo bhi ise sabse pehle right slove krega..... that i will mark as brainliest.... so pls pls slove kro ​

Answer 1

Hope it helps you and please mark me down as the brainliest and please follow me

Answer 2

SOLUTION

HEY! WHY YOU GIVE BRANLIEST ANSWER TO PREVIOUS QUESTION. PLEASE ALWAYS FIND SOLUTION WHICH TRYING TO USE SOME SORT OF YOUR BRAIN AND ALSO CHECK YOUR IQ LEVEL.

${x}^{2} + \frac{1}{ {x}^{2} } = \frac{82}{9} \\ \\ \: add \: 2 \: on \: both \: side \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = \frac{82}{9} + 2 \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2(1) = \frac{82 + 18}{9} \\ \\ write \: 1 \: as \: x \times \frac{1}{x} \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2(x)( \frac{1}{x} ) = \frac{100}{9} \\ \\ we \: know \: that \: {a}^{2} + {b}^{2} + 2ab = {(a + b)}^{2} \\ \\ {(x + \frac{1}{x} )}^{2} = \frac{100}{9} \\ x + \frac{1}{x} = \frac{10}{3} \\ \frac{ {x}^{2} + 1}{x} = \frac{10}{3} \\ \\ 3 {x}^{2} + 3 - 10x = 0 \\ \\ solving \: a \: quadratic \: equation \: is \: quite \: simple \: than \: solving \: a \: biquadratic \: equation \\ \\ 3 {x}^{2} - 10x + 3 = 0 \\ 3 {x}^{2} - 9x - x + 3 = 0 \\ 3x(x - 3) - 1(x - 3) = 0 \\ from \: here \: we \: get \: x = 3 \: or \: x = \frac{1}{3}$

THERE YOU GO NOT KAT NOW SHOW STOPPER.......