Question

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Answer 1

Sol1) Length of red ribbon= 5⅕m

Length of green ribbon=2½m

Total length = (5⅕+2½)m

=( 26/5+ 5/2) m

Take the Lcm of 5 and 2

LCM= 10

26×2/5×2 = 52/10 , 5×5/5×2=25/10

52+25/10 = 77/10

77÷10 = 7 (Quotient ) & 7 (Remainder)

= 7×7/10

Sol2) To divide 735 and 1155 exactly leaving no remainder ,we will take the HCF of 735 and 1155.

HCF is shown in pic given at top.

105 is the HCF.

So. 105 is that largest no.