Question

(
)
JO V
The total charge entering the terminal of ar
element is given by ;
q = (6ť - 12t)mC
The current at t = 3s is
(i) 12 mA (ii) 48 mA
(iii) 36 mA (iv) 24 mA



i need a clear
full explaination​

Answer 1

Answer:

i=  

dt

d(q(t))

​  

 

i=\dfrac{d(-12e^{-2t})}{dt}i=  

dt

d(−12e  

−2t

)

​  

 

(take the derivative)

i=24e^{-2t}i=24e  

−2t

 mA or i=0.024e^{-2t}i=0.024e  

−2t

 A

(First equation gives us mA while the second gives us A)