Question

joan had an unusual birthday by giving chocolates one week before her birthday,she would give one on the chocolate on the first day,3 chocolates on the second day,and 5 chocolates on the third and so on construct the sequence oh numbers showing the number showing the number of chocolates.how many chocolates would she have given away on her birthdate?

Answer 1

Answer:

She would give 15 chocolates on her birthday

Step-by-step explanation:

Before a week = 7 days before her birthday.

7 days before the birthday = 1

6 days before the birthday = 3

5 days before the birthday = 5

4 days before the birthday = 7

3 days before the birthday = 9

2 days before the birthday = 11

1 day before the birthday = 13

Number of chocolates given away on her birthday = 15

Total chocolates given BEFORE her birthday are 49

Total chocolates given away = 15 + 49 = 64