Question

Joe and Ahmad had 80 marbles altogether. Ahmed has 4 times as many marbles as Joe. How many males does each boy have

Answer 1

Answer:

Let m= the number of marbles Joe has

Let 4m=the number of marbles Ahmad has

m + 4m = 80

5m = 80

m=16

4m=4(16)=64 Check: 16+64=80 checks

ANSWER: Joe has 16 marbles and Ahmad has 64 marbles.

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Answer 2

Answer:

Ahmad has 64 marbles and Joe has 16 marbles.

Step-by-step explanation:

Let marble with Joe be x.

Then marbles with Ahmad = 4x (it is 4 times Joe's)

Marbles with both the boys together:

4x + x = 80

    5x = 80

      x = 80/5

      x = 16

Therefore, no. of marbles each boy has:

Ahmad = 4x = 16 x 4 = 64

Joe = x = 16

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