Joe and Ahmad had 80 marbles altogether. Ahmed has 4 times as many marbles as Joe. How many males does each boy have
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Answered by
4
Answer:
Let m= the number of marbles Joe has
Let 4m=the number of marbles Ahmad has
m + 4m = 80
5m = 80
m=16
4m=4(16)=64 Check: 16+64=80 checks
ANSWER: Joe has 16 marbles and Ahmad has 64 marbles.
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Answered by
1
Answer:
Ahmad has 64 marbles and Joe has 16 marbles.
Step-by-step explanation:
Let marble with Joe be x.
Then marbles with Ahmad = 4x (it is 4 times Joe's)
Marbles with both the boys together:
4x + x = 80
5x = 80
x = 80/5
x = 16
Therefore, no. of marbles each boy has:
Ahmad = 4x = 16 x 4 = 64
Joe = x = 16
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