Question

Joe is 8 years younger than Isabelle. The sum of their ages is 32. Find their present ages.

Answer 1

Step-by-step explanation:

Let the age of Isabelle be X. years

Joe=x-8 years

x+x-8=32

2x=32+8

x=40/2

x=20 years

Age of Isabelle=20 years

Joe=20-8=12 years

Hope It Helps

Answer 2

Step-by-step explanation:

let the age of Isabelle be x years and Joe be x -8 yrs

A/Q

= x -8+x = 32

= 2x- 8 = 32

= 2x= 32+8

= 2x = 40

= x = 40/2

therefore x,= 20

present years of Isabelle = 20 yrs

present years of Joe = 20-8 = 12 yrs .

the sum of their ages= 20 + 12 = 32 yrs

therefore the answer is verified..

hope it helps you.....