Joe used 3/10 of a box of cereal on Monday for baking and the rest on Tuesday . if he used 192 grams more cereal on Tuesday than on Monday, what was the total weight of cereal that he had at first ?
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Given Joe used 3/10 of a box of cereal on Monday for baking and the rest on Tuesday . if he used 192 grams more cereal on Tuesday than on Monday, what was the total weight of cereal that he had at first ?
- Let Monday and Tuesday be p and q and box be b
- So p + q = b
- So q = p + 192 (since Joe used 192 grams more on Tuesday)
- Now p = 3/10 of b on Monday
- Also q = 1 – 3/10 = 7/10 of b on Tuesday.
- Now the equation will be
- 7/10 b = 3/10 b + 192 (7/10 of box on Tuesday = 3/10 of b on Monday + 192 grams)
- 7/10 b – 3/10 b = 192
- 4/10 b = 192
- 4b = 1920
- Or b = 1920 / 4
- Or b = 480 grams.
- Therefore he had 480 grams at the beginning.
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