Question

Joel notices that the hands of his wrist watch coincide with each other every 45 minutes. How much time will his watch lose per day in this scenario?​

Answer 1

Given: the watch coincides at every 45 minuts.

To find: the amount of time that Joel's watch will lose per day.

Solution:

Find the time clock loses per day.

$\[ = \left( {\frac{{720}}{{11}} - M} \right)\left( {60 \times \frac{{24}}{M}} \right)\]$

$\[ = \left( {\frac{{720}}{{11}} - 64} \right)\left( {60 \times \frac{{24}}{{64}}} \right)\]$

$\[ = \frac{{16}}{{11}}\left( {60 \times \frac{3}{8}} \right)\]$

$\[ = \frac{2}{{11}} \times 60 \times 3\]$

$\[ = \frac{{360}}{{11}}\]$

$\[ = 32\frac{8}{{11}}\]$ minutes

Hence, the clock will loose$\[ 32\frac{8}{{11}}\]$ minutes per day.

Answer 2

Answer:

650.18

Step-by-step explanation: