Question

Joelle is working on a school report in a word processor. She wants to place an oversized image which is 30.51 \text{ cm}30.51 cm30, point, 51, space, c, m wide so that it appears centered on the page. The width of the page is 21.59 \text{ cm}21.59 cm21, point, 59, space, c, m. In the program, horizontal positions to the right of the leftmost edge of the page are positive.
What horizontal position for the left edge of the image should Joelle use to center the image?

Answer 1

Answer:

Step-by-step explanation:

First, you need to subtract 13.09 from the 21.59, which will give you 8.5 as the leftover space on the page. Then divide in half to find the left and right margin.

The answer is 4.25.

Answer 2

Answer:

-4.46cm

Step-by-step explanation:

The horizontal midpoint of the page is;

$\frac{21.59}{2}=10.795cm$

The horizontal midpoint of the image is given as;

$\frac{30.51}{2}=15.255cm$

For the image to be centered, these to midpoints must be on the same point in the axis.

If we take the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795cm.  The distance that goes beyond this leftmost edge is computed as;

$15.255-10.795=4.46cm$

On the axis, this is on the negative side. Therefore, the horizontal position for the left edge of the image that Joelle should use to center the image is -4.46cm.