Question

Joey participated in dance-a-thon his team started dancing at 10am on friday and stop at 6pm on saturday how many hours did joeys team dance. Step by step solving

Answer 1

Given :-

• Joey's dance team started dancing at 10AM on Friday.
• They stop at 6PM on saturday.

To Find :-

• For how many hours did joey's team dance. ?

Solution :-

we have given that, Joey's dance team started dancing at 10AM on Friday.

So,

→ 10AM + 2hours = 12 noon on friday.

After 2 hours it was 12 noon of friday and now, we know that, in 1 day we have total 24 hours.

Therefore, we can say that, from 12 noon on friday to 12 noon on saturday we have total 24 hours. { 12 noon to 12AM night = 12 hours night on friday and 12 AM night to 12 noon on saturday we again have 12 hours . So, 12 + 12 = 24 hours. }

Than,

→ Upto 12 noon Saturday Joey's team dance for = 2 hours(Before friday noon) + 24 hours(Friday noon to saturday noon.) = 2 + 24 = 26 hours.

Now,

The team stop at 6PM on saturday.

So,

→ from 12 noon on saturday to 6PM on saturday, we have = 6PM - 00:00 = 6 Hours.

Therefore,

→ Total Time Joey's team dance = 26 hours.(friday 10AM to saturday noon) + 6 hours(saturday noon to saturday 6PM) = 26 + 6 = 32 Hours. (Ans.)

Hence, Joey's team dance for 32 Hours.