Question

John and David agree to meet in California for the weekend. John travels 104 miles in the same time that David takes to travel 96 miles. If John’s rate of travel is 4 mph more than David’s, at what speed does John travel?

Answer 1

Answer:

52 mph

Step-by-step explanation:

Distance traveled by John = D1 = 104 miles

Distance traveled by David = D2 = 96 miles

Let John's Speed is V1 and David's Speed is V2.

John's speed is 4 mph more than David's speed,

V1 = V2 + 4...................Equation (1)

Now, we know that,

Speed = Distance / Time

V = D/T......................Equation (2)

Using Equation (1) and (2)

$V1 = V2 + 4\\\\ \frac{D1}{T} = \frac{D2}{T} + 4\\\\ \frac{D1-D2}{T} = 4\\\\\frac{104-96}{T} = 4\\\\ T = \frac{8}{4}\\\\ T = 2 Hours$

Now,

V1 = D1/T

V1 = 104/2

V1 = 52 mph