John and David agree to meet in California for the weekend. John travels 104 miles in the same time that David takes to travel 96 miles. If John’s rate of travel is 4 mph more than David’s, at what speed does John travel?
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Let speed of John be S km/hr and speed of David be (S + 4) km/hr.
John travels 104 miles in the same time that David takes to travel 96 miles.
Speed = Distance/Time
For John :
→ (S + 4) = 104/T
→ T = 104/(S + 4)
For David :
→ T = 96/S
Now, according to question;
Both John and David agree to meet in California for the weekend.
Means, times is same.
So,
→ 104/(S + 4) = 96/S
Cross multiply them
→ 104S = 96(S + 4)
→ 104S = 96S + 384
→ 104S - 96S = 384
→ 8S = 384
→ S = 576/8
→ S = 48
Answer :-
Speed of John = 48 km/hr.
Speed of David = (S + 4)
→ 48 + 4
→ 52 km/hr.
___________________________
Verification :-
=> 104/52 = 96/48
=> 2 = 2
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