Question

John and jivanti both have 45 Marbles in total both lose 55 Marbles and now they have 124 as the product of Marbles we would like to know how many Marbles they had in beginning ​

Answer 1

Given John and Jivanti together have 45 marbles

Let the number of Marbles John had be= x

Then the number of marbles jivanti had= 45-x

Both of them lost 5 Marbles each

Therefore, the number of marbles John had= x-5

The number of marbles jivanti had= 45-x-5= 40-x

Now product of the number of Marbles =124

Therefore , (x-5)(40-x)=124

40- x²-200+5x=124

-x²+45x-200-124=0

x² -45x+324=0. (Multiplying by(-1))

By factorisation method

x²-36x-9x+324=0

x(x-36) - 9(x-36)=0

(x-36)(x-9)=0

x=36 or x= 9

When John has 36 Marbles Jivanti has = 45 - x = 45 - 36 = 9 marbles

When John has 9 Marbles Jivanti has= 45 - x = 45 - 9 = 36 marbles

Amannnscharlie

Answer 2

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hope this helps u...