John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.
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Solution:
i)
Given John and jivanti together have 45 marbles
Let the number of Marbles John had be= x
Then the number of marbles jivanti had= 45-x
Both of them lost 5 Marbles each
Therefore, the number of marbles John had= x-5
The number of marbles jivanti had= 45-x-5= 40-x
Now product of the number of Marbles =124
Therefore , (x-5)(40-x)=124
40- x²-200+5x=124
-x²+45x-200-124=0
x² -45x+324=0. (Multiplying by(-1))
By factorisation method
x²-36x-9x+324=0
x(x-36) - 9(x-36)=0
(x-36)(x-9)=0
x=36 or x= 9
When John has 36 Marbles and jivanti has = 45-x= 45-36=9 marbles
When John has 9 Marbles and jivanti has= 45-x= 45- 9= 36 marbles
kajal9650:
wello☺️
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hope it helps you..........
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