Math, asked by dhruv763, 1 year ago

John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.​

Answers

Answered by Anonymous
45

Step-by-step explanation:

Solution:

i)

Given John and jivanti together have 45 marbles

Let the number of Marbles John had be= x

Then the number of marbles jivanti had= 45-x

Both of them lost 5 Marbles each

Therefore, the number of marbles John had= x-5

The number of marbles jivanti had= 45-x-5= 40-x

Now product of the number of Marbles =124

Therefore , (x-5)(40-x)=124

40- x²-200+5x=124

-x²+45x-200-124=0

x² -45x+324=0. (Multiplying by(-1))

By factorisation method

x²-36x-9x+324=0

x(x-36) - 9(x-36)=0

(x-36)(x-9)=0

x=36 or x= 9

When John has 36 Marbles and jivanti has = 45-x= 45-36=9 marbles

When John has 9 Marbles and jivanti has= 45-x= 45- 9= 36 marbles


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Answered by anmol4032
47

hope it helps you..........

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