Question

John and jivanti together have 45 Marbles both of them lost 5 Marbles each and the product of the number of Marbles they now have is 124 we would like to find out how many Marbles they had to start with

Answer 1

Answer:

Step-by-step explanation:

Let marbles John had be x and jivanti be y

x+y= 45

(x-5)(y-5)=124

y=45-x

(x-5)(40-x)=124

x^2-45x+324=0

(-45/2. +k)(-45/2-k)=324

2025/4 - k^2 = 18^2

[45/2]^2-18^2=k^2

k=+ or - 13+1/2

27/2-45/2=-18/2=-9

-27/2-45/2=-72/2=-36

(x-36)(x-9).  X=36 or 9

both are positive because y has been converted into its x form

y = 45-x=45-36=9. Or y = 45-9=36

john or jivanti had 9 marbles to start with.

jivanti or John respectively had 36 marbles to start with.

thank you and pls like my answer if you can.

Answer 2

Answer:

Let the number of john's marbles be x.

Therefore, number of jivanti's marble = 45 - x

After losing 5 marble,

Number of john's marbles = x - 5

Number of jivanti's marbles = 45 - x - 5 = 40 - x

The product of the number of marbles is 124.

Therefore,

=> (x - 5) (40 - x) = 124

=> 40x - x² - 200 + 5x = 124

=> x² - 45x + 200 = - 124

=> x² - 45x + 324 = 0

=> x² - 36x - 9x + 324 = 0

=> x(x - 36) - 9(x - 36) = 0

=> (x - 36) (x -9)

=> x - 36 = 0 or x - 9 = 0

=> x = 36 or x = 9

The number of john's marbles = 36

Thus, the number of jivanti's marbles = 45 - 36 = 9

Number of john's marbles = 9

Thus, number of jivanti's marbles = 45 - 9 = 36.

Step-by-step explanation: