John and jivanti together have 45 Marbles both of them lost 5 Marbles each and the product of the number of Marbles they now have is 124 we would like to find out how many Marbles they had to start with
Answers
Answer:
Step-by-step explanation:
Let marbles John had be x and jivanti be y
x+y= 45
(x-5)(y-5)=124
y=45-x
(x-5)(40-x)=124
x^2-45x+324=0
(-45/2. +k)(-45/2-k)=324
2025/4 - k^2 = 18^2
[45/2]^2-18^2=k^2
k=+ or - 13+1/2
27/2-45/2=-18/2=-9
-27/2-45/2=-72/2=-36
(x-36)(x-9). X=36 or 9
both are positive because y has been converted into its x form
y = 45-x=45-36=9. Or y = 45-9=36
john or jivanti had 9 marbles to start with.
jivanti or John respectively had 36 marbles to start with.
thank you and pls like my answer if you can.
Answer:
Let the number of john's marbles be x.
Therefore, number of jivanti's marble = 45 - x
After losing 5 marble,
Number of john's marbles = x - 5
Number of jivanti's marbles = 45 - x - 5 = 40 - x
The product of the number of marbles is 124.
Therefore,
=> (x - 5) (40 - x) = 124
=> 40x - x² - 200 + 5x = 124
=> x² - 45x + 200 = - 124
=> x² - 45x + 324 = 0
=> x² - 36x - 9x + 324 = 0
=> x(x - 36) - 9(x - 36) = 0
=> (x - 36) (x -9)
=> x - 36 = 0 or x - 9 = 0
=> x = 36 or x = 9
The number of john's marbles = 36
Thus, the number of jivanti's marbles = 45 - 36 = 9
Number of john's marbles = 9
Thus, number of jivanti's marbles = 45 - 9 = 36.
Step-by-step explanation: