Question

John bought a computer scanner and supplies for $215.70, which will allow him to scan images for $0.34 each. A computer center charges $0.59 to scan each image. How many images must John scan before his total cost is less than getting scanned images at the computer center?

Answer 1

Bro it's a go*gled image please don't report and mark as brainliest

Answer 2

Given:- Cost of scanner= 215.70

charges= 0.59

per image rupees= 0.34

To find:- No of images-

Solution:- To find the total number of images to be scanned:

The first step is to set up an equation with S the number of scans;

{- {{.34s + 215.70 <= .59s}}}

First basic equation obtained from above conditions

Then solve it further:-

.34s+215.70-.59s<= .59s-.59s

-.25s+215.70<= 0

-0.25s<=0-215.70

-0.25s<=-215.70

Divide it by 0.25 term

therefore we get

s<=215.70/0.25

Hence s<=862.8

Take s as 863 approximate

So John must scan at least 863 images before he pays less on his own rather than in the store