Question

John feeds three cows on his dairy farm the following daily diets:

Larry eats Three-fourths of a pound of hay.
Mo eats 1One-half pounds of hay.
Curly eats Four-sixths of a pound of hay.
Do Larry and Curly together eat more or less hay than Mo?

Larry and Curly eat
pounds of hay together.

The amount of hay Mo eats is
the amount that Larry and Curly eat combined.

Answer 1

Larry and Curly eat 1 5/12 together

Step-by-step explanation:

4/6 + 3/4 = 1 5/12

1 5/12 > 1/2

Answer 2

Step-by-step explanation:

• If Mo eats 1 1/2 pounds of hay, Larry and Curly together eat less.
• f Mo eats 1 1/2 pounds of hay, Larry and Curly together eat less.Larry and Curly eat 17/12 or 1 5/12 pounds of hay together.
• f Mo eats 1 1/2 pounds of hay, Larry and Curly together eat less.Larry and Curly eat 17/12 or 1 5/12 pounds of hay together.Mo eats more hay than Larry and Curly combined.
• f Mo eats 1 1/2 pounds of hay, Larry and Curly together eat less.Larry and Curly eat 17/12 or 1 5/12 pounds of hay together.Mo eats more hay than Larry and Curly combined.Step-by-step explanation: Add the fractions by finding the Least Common Denominator 3/4 = 9/12. 4/6 = 8/12.
• f Mo eats 1 1/2 pounds of hay, Larry and Curly together eat less.Larry and Curly eat 17/12 or 1 5/12 pounds of hay together.Mo eats more hay than Larry and Curly combined.Step-by-step explanation: Add the fractions by finding the Least Common Denominator 3/4 = 9/12. 4/6 = 8/12.9/12 +8/12 =17/12.
• f Mo eats 1 1/2 pounds of hay, Larry and Curly together eat less.Larry and Curly eat 17/12 or 1 5/12 pounds of hay together.Mo eats more hay than Larry and Curly combined.Step-by-step explanation: Add the fractions by finding the Least Common Denominator 3/4 = 9/12. 4/6 = 8/12.9/12 +8/12 =17/12.1 1/2 = 18/12