John goes to school from his home at a speed of 4 km/h. If he walks at a speed of 5 km/h,
hen he reaches the school 7 minutes early. Find the distance between the school and the
home.
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Answer: let time T be the time when he reaches at time and D be distance of school from home
∴ T = D / 4 ........................(1)
When he walks at 5 km/h , he reaches 7 min early
T - 7/60 = D/5 ...................(2)
Subtracting (2) from (1) and solving further we get
D = 7/3 KM
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