Math, asked by sneha21028, 9 months ago

John got a price of 75000 in a TV contest he paid 1 by 10 of the prize as the income tax. Out of the remaining he gave 1 by 3 to his son and 1 by 5 to his daughter 1 by 10 to the Red Cross Society and rest to his wife .. what portion of the prize did John's wife get ​

Answers

Answered by tennetiraj86
15

Answer:

His wife gets 32,400 rupees is the answer for the given problem

Attachments:
Answered by mainaswain123
85

Answer:

Hey mate, this is your correct answer.

Step-by-step explanation:

John got a prize of 75000 in a tv contest

He paid 1/10 of the prize as the income tax = 1/10 of 75000 = Rs. 7500

Out of the remaining he gave 1/3 to his son = 1/3 of (75000 - 7500) = 1/3 of 67500 = Rs. 22500

he gave 1/5 to his daughter = 1/5 of 67500 = Rs. 13500

He gave 1/10 to the Ted cross society = 1/10 of 67500 = Rs. 6750

The remaining amount he has given to his wife = 75000 - 7500 - 22500 - 13500 - 6750 = Rs. 24750

So the portion of the prize did John's wife get is ₹ 24750.

Pls mark me as the brainliest.

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