Math, asked by kumarnaresh23203, 7 months ago

John got a prize of ₹75000 in a TV contest he paid 1/10 of the prize as the income tax out of the remaining he gave 1/3 to his daughter 1/5 to his daughter 1/10 to the red cross society and the rest to his wife what portion of the prize did John wife get and how much

Answers

Answered by Rppvian2020
13

Step-by-step explanation:

Amount left for wife = 24750 Portion

( % ) left to wife = 33 %

Step - by - step explanation :

Total prize money = Rs 75,000 Paid as incometax = 1/10 of 75,000 = 7,500 Remaining amount = 75000 - 7500 = 67,500

Amount to son = 1/3 of remaining = 1/3 of 67500 = 22,500 Amount to daughter = 1/5 of remaining = 1/5 of 67500 = 13,500 Amount to RedCross Society = 1/10 of remaining = 1/10 of 67500 = 6,750 Total from remaining amount = ( 22500 + 13500 + 6750 ) = 42750 Amount left for wife = 67500 - 42750 = 24750 Portion ( % ) left to wife = ( 24750/75000 )

* 100 = 33 %

Answered by tanishkasahuspc
0

this is the answer step by step

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