Math, asked by mohinichatterjee1, 11 months ago

John got a prize of Rs.75000. He paid 1/10 of it as income tax. Out of the remaining, he gave 1/3 to his son, 1/5 to his daughter and 1/10 to The Red Cross Community and the rest to his wife. What portion of the prize did his wife get and and how much money did she get?

Answers

Answered by IntelBee
41

Answer:

Amount left for wife =  24750

Portion (%) left to wife =  33%

Step-by-step explanation:

Total prize money = Rs 75,000

Paid as incometax = 1/10 of 75,000 = 7,500

Remaining amount = 75000 - 7500 = 67,500

Amount to son = 1/3 of remaining = 1/3 of 67500 = 22,500

Amount to daughter = 1/5 of remaining = 1/5 of 67500 = 13,500

Amount to RedCross Society= 1/10 of remaining = 1/10 of 67500 = 6,750

Total from remaining amount = (22500+13500+6750) = 42750

Amount left for wife = 67500 - 42750 = 24750

Portion (%) left to wife = (24750/75000 ) * 100 = 33%

Answered by Rppvian2020
14

Answer:

Amount left for wife = 24750 Portion ( % ) left to wife = 33 % Step - by - step explanation : Total prize money = Rs 75,000 Paid as incometax = 1/10 of 75,000 = 7,500 Remaining amount = 75000 - 7500 = 67,500 Amount to son = 1/3 of remaining = 1/3 of 67500 = 22,500 Amount to daughter = 1/5 of remaining = 1/5 of 67500 = 13,500 Amount to RedCross Society = 1/10 of remaining = 1/10 of 67500 = 6,750 Total from remaining amount = ( 22500 + 13500 + 6750 ) = 42750 Amount left for wife = 67500 - 42750 = 24750 Portion ( % ) left to wife = ( 24750/75000 ) * 100 = 33 %

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