Question

John has 1050 with him. Every day, he saves 50. In how many days will his savings be 3000?​

Answer 1

I GOT YOUR ANSWER

HOPE U UNDERSTAND

Answer 2

Answer:

${\bold{\therefore 40\:Days}}$

Step-by-step explanation:

${\bold{\huge{\underline{SOLUTION-}}}}$

• In the given question information given about a series of A.P whose common difference are same and last term is given.

• We have to find the number of days in which john have 3000 rupees.

$\underline \bold{Given : } \\ \implies First \: term(a) = 1050 \\ \implies Common \: difference(d) = 50 \\ \implies Last \: term( a_{n}) = 3000 \\ \\ \underline \bold{to \: find : } \\ \implies No. \: of \: days(n) = ?$

• According to given question :

$\bold{By \: nth \: term \: formula : } \\ \implies a_{n} = a + (n - 1)d \\ \bold{Putting \: given \: values} \\ \implies 3000 = 1050 + (n - 1) \times 50 \\ \implies 3000 - 1050 = 50n - 50 \\ \implies 1950 = 50n - 50 \\ \implies 1950 + 50 = 50n \\ \implies 2000 = 50n \\ \implies n = \frac{2000}{50} \\ \bold{\implies n = 40} \\ \\ \bold{\therefore \: After \: 40 \: days \: john \: have \: 3000rupees}$