Question

John has bought a 4 Gbyte MP3 player.
(You may assume: 1 byte = 8 bits, 1 Mbyte = 1024 kbytes and 1Gbyte = 1024 Mbytes)

(i) We can assume that each song lasts 3 minutes and is recorded at 128 kbps (kilobits per second). How much memory is required per song?

Answer 1

Answer:

second in 3 minutes is

3×60=180

song record 128 kbps then

total memory is

180×128=23040 kb per 180 second

now convert 23040kb into mb

23040÷8=2,880

this mean 2.8 mb per song