Question

John is as much younger to Anup as he is older to Pawan. If the sum of the ages of Anup and Pawanis 48 years, what is the age of John?

Answer 1

Step-by-step explanation:

John=x

Anup=x+p(value of P greater than zero)

Pawan=x-p

(X+P) +(X-P) =48

2X=48

X=24

Answer 2

Given:

John is as much younger to Anup as he is older to Pawan. The sum of the ages of Anup and Pawan is 48 years.

To find:

The age of John.

Solution:

The age of John is 24 years.

To answer this question, we will follow the following steps:

Let the present age of John be x years and he is 'p' years younger than Anup

Similarly,

The John is 'p' years older than Pawan

Now,

According to the question, we have,

The age of Anup

$= (x + p) \: years$

The age of Pawan

$= (x - p) \: years$

The sum of ages of Anup and Pawan = 48 years

So,

$(x + p) + (x - p) = 48$

$2x = 48$

$x = 24 \: years$

Hence, the age of John is 24 years.