Question

John is riding the Giant Drop at Canada. If John free falls for 3 seconds, what will be his final velocity and how far will he fall? acceleration due to gravity(g)=10 m/s2​

Answer 1

Explanation:

Here, u is the initial speed, v is the final velocity, g is the acceleration due to gravity and t is the time taken. It is given in the problem that john is riding a giant drop at canada if john free falls for 2.6 s. Put g= 9.8 meter per second square, t= 2.6 s and u = 0. Therefore, the final velocity is 25.48 m\s

Hope it helps

Answer 2

Answer: The correct answers are 30.00 m\s^2

The expression for the equation of the motion during free fall condition is as follows;

v= u+at

Here, u is the initial speed, v is the final velocity, g is the acceleration due to gravity and t is the time taken.

It is given in the problem that john is riding a giant drop at Canada if john free falls for 3.0 s.

Put g= 10 meter per second square, t= 3.0 s and u = 0.

v= 0+(10)(3.0)

v= 30.00 m\s^2

Therefore, the final velocity is 30.00 m\s^2.