Question

John Peter can complete a work in 20 hours and 25 hours respectively then find first work done by both together in 4 hours second work left after both work together for 4 hours third time taken by Peter to complete the remaining work​

Answer 1

Answer:

Step-by-step explanation:

Let total  work be x

1 hour work of John =1/20

1 hour work of Peter = 1/25

1 hour work of john and peter=1/20+1/25

4 hour work of john and peter=4/20+4/25

=1/5+4/25

=9/25

work left after 4 hours=x - 9/25

time taken by peter to do the remaining work=( 9/25 )/(1/25)

=9/25 x 25/1

=9 hours