Question

John’s birthday cake is a delightful cylinder of radius 6 inches and height 3 inches . If these friends cut the cake into 8 equal sectors the total surface area of the piece of cake in sq. inches

Answer 1

Hi dear

I also get 600 + 60π

The cylinder has surface are determined by

SA = 2πr2 + 2πrh

The surface area of the cube is 6s2 with s representing the length of a side

This leads us initially to SA of the cake = 2πr2 + 2πrh + 6s2

In this case though, since the bottom the cylinder is on the top of the cake

the circular area composing the bottom part of the cylinder is not included

in the surface area so we subtract πr2 Leaving

SA = πr2 + 2πrh + 6s2 for the cake

Note: the same amount of area is also covered on the top of the cube so

this same amount is subtracted from the equation again...

The final equation for the surface area of the cake is

SA = 2πrh + 6s2

Since the diameter of the cylinder is 6, then r = 3, h = 10, s = 10

SA = 2π(3)(10) + 6(10)2

= 60π + 600

Brainiest answer please.

Answer 2

The correct answer is to cut the cake in quarters (4 pieces) using 2 of the cuts – one horizontally down the center of the cake and the other vertically down the center of the cake. This will leave you with 4 pieces (or slices) of cake. Then, you can take all 4 pieces and arrange them in a stack that is 4 pieces high. Finally, you can just cut that stack of 4 pieces in half – using your third and final cut – and then you will end up with 8 pieces of cake!