Physics, asked by roopal9929, 1 year ago

john takes 10 hours for his trip. for the first five hours his average speed was 40mph. for the next five hours his average speed was 50mph. what was john's average speed during his journey?

Answers

Answered by santy2
3

The speed is in meters per hour.

In the first five hours the distance covered is :

5 × 40 = 200 m

In the second 5 hours the distance covered is :

5 × 50 = 250m

Average speed = Total distance / Total time

Total distance = 250 + 200 = 450 m

Total time = 10 hours.

Average speed = 450/10 = 45

= 45 meters per hour

Answered by branta
0

Answer:

John's average speed during his journey is 45 meter per hour.

Explanation:

The distance travelled by John in first five hour is given by,

Distance = speed × time

Distance = 40 mph × 5 hour

Distance = 200 meter

The distance travelled by John in next five hour is given by,

Distance = speed × time

Distance = 50 mph × 5 hour

Distance = 250 meter

Total distance travelled by John is given by,

Total distance = 200 + 250 = 450 meter

Total time taken to travel total distance is given by,

Total time = 10 hour

Average speed is given by,

Average speed = \frac{Total distance}{Total time}

Average speed = \frac{450}{10}

Average speed =45 meter per hour

John's average speed during his journey is 45 meter per hour.


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