Question

John walks 10 miles at an average rate of 2 miles per hour and returns on a bicycle at

an average rate of 10 miles per hour. How long (to the nearest hour) does the entire

trip take him ?​

Answer 1

Step-by-step explanation:

John walks d=10mil at an average rate of s=2+mph

since d=s%2At, we have

10mil=2mph%2At

10mil%2F2mph=t

5h=t......John walks for 5h

and returns on a bicycle at an average rate of s=10+mph

since distance is same we will have

10mil=10mph%2At

10mil%2F10mph=t

1h=t

the entire trip takes him 5h%2B1h=6h

so, the answer is: D) 6 hours

this is your answer

Answer 2

Answer:

3hr

Step-by-step explanation:

10 miles each side he covers 5 miles

at 2 miles per hour it's 2 hr 30 min

at 10 miles per hour it's 30 min