Question

Johor had a bêtiful garden in the from of a quadrant of raclius Im as shown , the wanted to fence it to protect the flowers. Find the length of wire required to fence at completely (d) 36m 11 m (6) 18m (c) 25m​

Answer 1

Answer:

Solution:

Here, plants = 1000

Since the remainder is 39.

Therefore 31^2<100031

2

<1000

Next perfect square number 32^2=102432

2

=1024

Hence, number to be added

= 1024 – 1000 = 24

\therefore1000+24=1024∴1000+24=1024

Hence, the gardener required 24 more plants.

Answer 2

Given:

A quadrant of radius = 7 m

To Find:

Length of wire required to fence the quadrant

Solution:

• To find the length of wire required to fence the garden completely, we need to find the perimeter of the quadrant.
• The perimeter of the circle is given by:

                         Perimeter = 2πr

where r is the radius of the circle

• Since quadrant is $\frac{1}{4}$ that of a circle its perimeter will be given by:

                       P= $\frac{1}{2}$πr + 2r       (2r term added for the boundary of thegarden)

Substituting known values in formula:

                      ⇒P = $\frac{1}{2}$ × 3.14 × 7 + 2(7)

                      ⇒P = 10.99 + 14

                      ⇒P = 24.99 m

                      ⇒ P≈ 25 m

Therefore, the length of wire required to fence the garden completely is (c) 25m​.