joker what happened???? The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP......Dont answer please
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Answered by
1
Answer:
Acc. to 1st condition,
t3 + t7 = 6 -----(1)
Acc. to 2nd condition,
t3 × t7 = 8 ----- (2)
a + 2d + a + 6d = 6
2a + 8d = 6 ----- (3)
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Answered by
1
Answer:
According to the conditions ;
a + 2d + a + 6d = 6
2a + 8d = 6
a + 4d = 3
a = 3 - 4d ----(1)
( a + 2d ) ( a + 6d ) = 8 ---(2)
substituting eq (1) in eq (2)
(3 - 4d + 2d )( 3 - 4d + 6d ) = 8
(3 - 2d)( 3 + 2d) = 8
9 - 4d^2 =8
4d^2 = 1
d^2 = 1 / 4
d = 1 / 2 ---(3)
substituting eq (3) in eq (1)
a = 3 - 4d
= 3 - 4 / 2
= 3 - 2
= 1
a = 1 and d = 1 / 2
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