Question

Jon wants to find the spring constant of a given spring, so he hangs the spring vertically and attaches a 0.40 kg mass to the spring’s other end. If the spring stretches 3.0 cm from its equilibrium position, what is the spring constant?

Answer 1

Answer:400/3

Explanation: we know that F=-kx

So, 0.4 × 10 N = k 3×10^-2

Solving this we get k= 400/3 = 133.33.