Math, asked by royal568, 1 year ago

Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:

(a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much

Answers

Answered by Anonymous
2

Answer:

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

We know that

Speed = Distance/Time.

Or, Time = Distance/Speed.

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

So we can clearly see that his new time compared with the old time was: twice as much.

Answer: (b)

hope this will help u:)

Answered by sidrocks09
0

Answer:

B. twice as much

Step-by-step explanation:

let his time taken on the first trip be T1 and his speed be V1

V1 = distance/T1= 150/T1

let his time taken on the second trip be T2 and speed V2

V2= distance/T2=300/T2

but, as given it's also equal to 3 times V1 thus,

300/T2 = 150/T1

which gives us the relation between T1 and T2 as,

T2 = 2 . T1

There you go:)

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