Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:
(a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much
Answers
Answer:
Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
We know that
Speed = Distance/Time.
Or, Time = Distance/Speed.
So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.
And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.
= 100/x hr.
So we can clearly see that his new time compared with the old time was: twice as much.
Answer: (b)
hope this will help u:)
Answer:
B. twice as much
Step-by-step explanation:
let his time taken on the first trip be T1 and his speed be V1
V1 = distance/T1= 150/T1
let his time taken on the second trip be T2 and speed V2
V2= distance/T2=300/T2
but, as given it's also equal to 3 times V1 thus,
300/T2 = 150/T1
which gives us the relation between T1 and T2 as,
T2 = 2 . T1
There you go:)