Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:
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Answered by
3
Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.
We know that
Speed = Distance/Time.
Or, Time = Distance/Speed.
So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.
And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.
= 100/x hr.
We know that
Speed = Distance/Time.
Or, Time = Distance/Speed.
So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.
And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.
= 100/x hr.
Answered by
2
Time = Distance/speed
Case 1
t1 = 50/v1
Case 2
t2 = 300/3v1 = 100/v1
t2/t1 = 2
So the new time is double of the initial time.
Case 1
t1 = 50/v1
Case 2
t2 = 300/3v1 = 100/v1
t2/t1 = 2
So the new time is double of the initial time.
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