Math, asked by karma496, 1 year ago

Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:

(a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much ​

Answers

Answered by QueenOfKnowledge
0

Solution:

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

We know that

Speed = Distance/Time.

Or, Time = Distance/Speed.

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

So we can clearly see that his new time compared with the old time was: twice as much.

Answer: (b)

Answered by FisahFisah
0

Answer:

1st step is

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

=======================

You know speed formula..

=======================

Speed = Distance/Time.

Or Time = Distance/Speed.

times taken to covered

a distance of 50 miles on his first trip = 50/x hr. Okey

Then......

And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

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