Jorge throws a ball vertically upward from a height of 0.90 m with an initial velociry of=1.4m/s
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Explanation:
The only force acting on the ball is the force of gravity. The ball will ascend until gravity reduces its velocity to zero and then it will descend. Find the time it takes for the ball to reach its maximum height and then double the time to cover the round trip.
Using v=u+at=u−gt, we get:
0m/s=50m/s−(10m/s
2
)t
Therefore,
t=(50m/s)/(10m/s
2
)=5s
This is the time it takes the ball to reach its maximum height. The total round trip time is 2t=10s.
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